3 equal charge having a magnitude of 2 micro coulomb are placed at the three corner of a right angle triangle of side 3cm,4cm and 5cm .then find the force on the charge at the right angle corner
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Three equal charges each
2μC
are placed the comers of a right angled triangle ABC. The force on charge at B due to charge at A is
F⃗ 1=14πε0(2μC)(2μC)(AB)2
(along BA)
F⃗ 1=14πε04×10−12(0.03)2N
(along BA) The force on charge at B due to charge at C is
F⃗ 2=14πε0(2μC)(2μC)(BC)2
(along BC)
F⃗ 2=14πε04×
Hope it helps....
2μC
are placed the comers of a right angled triangle ABC. The force on charge at B due to charge at A is
F⃗ 1=14πε0(2μC)(2μC)(AB)2
(along BA)
F⃗ 1=14πε04×10−12(0.03)2N
(along BA) The force on charge at B due to charge at C is
F⃗ 2=14πε0(2μC)(2μC)(BC)2
(along BC)
F⃗ 2=14πε04×
Hope it helps....
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