3 equal cubes are placed adjacent to each other in a row find the ratio of the total aurface area of cyboid thus formed to the sum of the surface area of the 3 cube
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surfaces area of cube =6x(side length)^2
let L is the side length of cube
surface area of all cube =18L^2
hence,
cuboid ,
length=3L
width =L
height=L
now total surace area of cuboid =2(3L^2+L^2+3L^2)=14L^2
now ,
ratio of both
surface area of cuboid/surface area of all 3 cube =14L^2/18L^2=7/9
let L is the side length of cube
surface area of all cube =18L^2
hence,
cuboid ,
length=3L
width =L
height=L
now total surace area of cuboid =2(3L^2+L^2+3L^2)=14L^2
now ,
ratio of both
surface area of cuboid/surface area of all 3 cube =14L^2/18L^2=7/9
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