Question

3 equal cubes each side 7 cm are joined end to end .find the surface area of resulting cuboid​

Answer 1

Given :-

• 3 equal cubes each side 7 cm are joined end to end.

To Find :-

• Surface Area of Resulting Cuboid.

Solution :-

As per the Question,

Length = 21cm.

Breadth = 7cm.

Height = 7cm.

Now, Calculating Surface Area.

= 2(lb + bh + hl).

= 2(21 × 7 + 7 × 7 + 7 × 21).

= 2(147 + 49 + 147).

= 2(343).

= 686 cm²

Therefore,

• Surface Area of cuboid = 686 cm².

Answer 2

Question :-

3 equal cubes each side 7 cm are joined end to end .find the surface area of resulting cuboid.

Answer :-

• Surface Area of cuboid = 686 cm².

Given :-

• Side = 7 cm { 3 cubes }

Have to Find :-

• What is the Surface Area of Resulting Cuboid .

Calculations :-

We know that ,

Surface area of the cuboid = = 2(lb + bh + hl).

Now ,

Substituting the values in the above formula :-

↬ 2(21 × 7 + 7 × 7 + 7 × 21).

↬ 2(147 + 49 + 147).

↬ 2(343).

↬ 686 cm²

Hence ,

The required answer is = $686 {cm}^{2}$

Additional Information :-

• Perimeter of Rectangle = 2( L + B )
• Perimeter of square = 4 × Side
• Perimeter of triangle = AB + BC + CA
• Area of Rectangle = L × B
• Area of Square = ( side ) ²
• Area of Rhombus = Product of Diagonal/2.
• Area of Parallelogram = Base × Height.
• Area of triangle = ½ × base × height .