Question

3. Evalute each of the following using suitable
Indentities
3
(999

.)3​

Answer 1

Answer:

(999)³ can be written as (1000-1)³

(a-b)³ = a³ - b³ - 3ab(a-b)

= (1000)³ - (1)³ - 3 × 1000 × 1 (1000-1)

= 1,000,000,000 - 1 - 3000(999)

= 9,99,999,999 - 2997000

= 997002999

I hope this helps you