Math, asked by jyothibhat291531, 2 months ago

3) Factorise 49x² - 36​

Answers

Answered by keerthanaarragudla
2

(7x-6)(7x+6) this is the answer

hope it is useful and mark me brainliest

have a great day. ...

Answered by ItzBrainlyBeast
13

\large\textsf{\underline\textcolor{aqua}{↭ \; \; AnSwEr :- }}

\large\textsf{                                                               }

\qquad\tt{:}\longrightarrow\boxed{\large\textsf\textcolor{orange}{( 7x + 6 ) ( 7x - 6 )}}

\large\textsf{                                                               }

\large\textsf{\underline\textcolor{aqua}{↭ \; \; ExPlAnAtIoN :- }}

\large\textsf{                                                               }

  • The equation 49x² - 36 = 0 can be written in the form of ( 7x )² - 6² = 0 . Now we can see that this equation is in the form of - = ( a + b )( a - b )

\large\textsf{                                                               }

\LARGE\mathfrak{\underline\textcolor{aqua}{✯\; Formula :-}}

\large\textsf{                                                               }

\qquad\tt{:}\longrightarrow\boxed{\large\textsf\textcolor{purple}{ a² - b² = ( a + b )( a - b )}}

\large\textsf{                                                               }

\LARGE\mathfrak{\underline\textcolor{aqua}{✯\; Solution :-}}

\large\textsf{                                                               }

\qquad\tt{:}\longrightarrow\large\textsf{49x² - 36 = ( 7x )² - 6² }

\qquad\tt{}\therefore\; \; \; \boxed{\large\textsf\textcolor{red}{( 7x² ) - 6² = ( 7x + 6 )( 7x - 6 )}}

\large\textsf{                                                               }

\LARGE\mathfrak{\underline\textcolor{aqua}{✯\; More \; \; Formulas :-}}

\large\textsf{                                                               }

\qquad\tt{:}\longrightarrow\large\textsf{( a + b )² = a² + b² + 2ab}

\qquad\tt{:}\longrightarrow\large\textsf{( a - b )² = a² + b² - 2ab}

\qquad\tt{:}\longrightarrow\large\textsf{a² - b² = ( a + b ) ( a - b )}

\qquad\tt{:}\longrightarrow\large\textsf{a² + b² = ( a + b )² - 2ab}

\qquad\tt{:}\longrightarrow\large\textsf{a³ + b³ = ( a + b ) ( a² - 2ab + b² )}

\qquad\tt{:}\longrightarrow\large\textsf{a³ - b³ = ( a - b ) ( a² + ab + b² )}

\qquad\tt{:}\longrightarrow\large\textsf{( a + b + c )² = a² + b² + c² + 2ab + 2bc + 2ac }

\large\textsf{                                                               }

\large\textsf\textcolor{purple}{     \; \; \; \;   \; \; \; \; \; \; \; \;                ◈ ━━━━━━━ ✪ ━━━━━━━ ◈}

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