Math, asked by sonu7004661171, 2 months ago

3. Factorise x - 14x+48​

Answers

Answered by ItzMeMukku
16

Answer:

\large \text{$(x-6)(x-8)$}(x−6)(x−8)</p><p>Step-by-step explanation:</p><p>\begin{gathered}\large \text{we have to factorise $x^2-14x+48$}\\\\\\\large \text{By splitting mid term}\\\\\\\large \text{we have to make $(ac=+-b)$}\\\\\\\large \text{48=$8\times6$}\\\\\\\large \text{$p(x)=x^2-8x-6x+48$}\\\\\\\large \text{$p(x)=x(x-8)-6(x-8)$}\\\\\\\large \text{$p(x)=(x-6)(x-8)$}\end{gathered}

\begin{gathered}\large \text{Zeroes of p(x)}\\\\\\\large \text{$x-6=0$}\\\\\\\large \text{$x=6$ or $x-8=0$}\\\\\\\large \text{$x=8$}\\\\\\\large \text{Thus we factorise p(x) and we two factors (x-6) and (x-8)}\end{gathered}

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Answered by guptajitendrabca1
17

Step-by-step explanation:

X - 14X +48

-13X +48

this is right answer

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