Math, asked by Arcel, 11 months ago

3. Fcatorise: (i) 6x^2 + 7x – 3 (ii) 2y^2 – 7^y – 15. Please required usgently freinds..

Answers

Answered by madhura41
1
Heya ✌✌
Here is u r Ans ➡

✨ 1) ➡

 = 6x {}^{2} + 7x - 3

 = 6x {}^{2} + 9x - 2x - 3

 = 3x \times (2x + 3) - (2x + 3)

 = (2x + 3)(3x - 1)

✨2) ➡

 = 2y {}^{2} - 7y - 15

 = 2y {}^{2} + 3y - 10y - 15

 = y \times (2y + 3) - 10y - 15

 = y \times (2y + 3) - 5(2y + 3)

 = (2y + 3)(y - 5)

Q .Factorise

(x3 + 7x2 + 7x -15 )

= x × 3 + 7x × 2 + 7x -15

= x × 3 + 21x -15

= 3(x + 7x -5 )

= 3(8x - 5 )

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Hope This Helps u ☺.

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Answered by varadad25
2

Given :-

(i) 6x^2 + 7x - 3

(ii) 2y^2 - 7y - 15

To find :-

Factors of (i) & (ii)

Solution :-

(i)

6 {x}^{2}  + 7x - 3 \\  = 6 {x}^{2}  + 9x - 2x - 3 \\  = 3x(2x + 3) - 1(2x + 3) \\  = (2x + 3)(3x - 1)

(ii)

2 {y}^{2}  - 7y - 15 \\  = 2 {y}^{2}  - 10y  + 3y - 15 \\  = 2y(y - 5) \: 3(y - 5) \\  = (y - 5)(2y + 3)

Ans. :-

(i) 6x^2 - 6x - 3 ==> (2x + 3) (3x - 1)

(ii) 2y^2 - 7y - 15 ==> (y - 5) (2y + 3)

Hope it helps.

Thanks my answers.

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