Question

3 Figure 3.34 shows a 2.0 V potentiometer used for the determination
of internal resistance of a 1.5 V cell. The balance point of the cell in
open circuit is 76.3 cm. When a resistor of 9.5 2 is used in the external
circuit of the cell, the balance point shifts to 64.8 cm length of the
potentiometer wire. Determine the internal resistance of the cell.​

Answer 1

Answer:

The expression of internal resistance of  a cell in potentiometer is given by

r=R[l2l1−1]

or r=9.5[64.876.3−1]=1.69Ω

Answer 2

Explanation:

The figure shows a 2.0 V potentiometer used for the determination of internal resistance of a 1.5 V cell. The balance point of the cell in open circuit is 76.3 cm. When a resistor of 9.5Ω is used in the external circuit of the cell, the balance point shifts to 64.8 cm length of the potentiometer. The internal resistance of the cell is



A .

1.63Ω

B .

1.66Ω

C .

1.69Ω

D .

1.72Ω