Math, asked by sirisha1417, 7 months ago


3) Find a quadratic polynomial, the sum & product
of whose Zeroes
are -3/2 and -1 respectively?

Answers

Answered by mathdude500
1

Answer:

sum \: of \: zeroes \:  =  \frac{ -3 }{2}  - 1 =  \frac{ - 5}{2}  \\ product \: of \: zeroes \:  =  \frac{ - 3}{2}  \times ( - 1) =  \frac{3}{2} \\ so \: required \: quadratic \: polynomial \: is \\ p(x) = k( {x}^{2}  -  \frac{( - 5)}{2} x +  \frac{3}{2} ) where \: k \: is \: non \: zero \: real \: number

Answered by holevedant11
0
x² + 3x + 2
= x² + 2x + x + 2 = 0
= x(x+ 2) + 1 ( x + 2 ) = 0
= ( x+1 ) ( x + 2 ) = 0
= x = -1 , -2


α + ß = -3
α ß = 2


QUADRATIC POLYNOMIAL

= x² - ( α + ß )x + α ß
= x² - (-3)x + 2
= x² + 3x + 2
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