3.
find
area and perimeter of the rectangle
whose breadth is 40cm and diagonal
is 49 cm.also find length
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answer: As we can see in the rectangle,
By Pythagoras theorem,
Now as given in the question,
Diagonal = 41 cm.
Length = 40 cm.
So, Putting these value we get,
Hence the width of the rectangle is 9 cm.
So
The perimeter of the rectangle = 2 ( Length + Width )
= 2 ( 40 cm + 9 cm )
= 2 x 49 cm
= 98 cm
Hence the perimeter of the rectangle is 98 cm.
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