3. Find each of the following products:
a) ( x²– 3x + 7)( 2x + 3)
b) (9x²– x + 15)( x²– x – 1)
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Answers
Answered by
1
Answer:
(i) _
Given (x³−3x+7)×(2x+3)
To find the product of given expression we have to use horizontal method.
In that we have to multiply each term of one expression with each term of another
Expression so by multiplying we get,
(x³−3x+7)×(2x+3)
⇒2x(x²−3x+7)+3(x²−3x+7)
⇒2x³−6x²+14x+3x²−9x+21
⇒2x³−3x²+5x+21
(ii) _
given ( 9x²- x + 15 ) ( x²- x- 1 )
9x⁴ + 9x³ + 9 + x³ + x² + x - 15x² - 15x - 15
9x⁴ + 10x³ - 14x² - 6
Answered by
0
Answer:
Step-by-step explanation:
(x) ^2 + (7)^2 - 2(x) (7)
(x^2 + 49 - 14x) (2x +3)
[x^2 + (7 +7) - 14x] (2x + 3)
(x^2 + 7 + 7 - 14x) (2x + 3)
Now, by using Splitting the middle term:
= 1(x^2 + 7) + 7 (1 - 2x)
= (x^2 + 7) (1 + 7) is the answer.
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