Math, asked by garimachandra90, 4 months ago


3. Find each of the following products:

a) ( x²– 3x + 7)( 2x + 3)

b) (9x²– x + 15)( x²– x – 1)


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Answers

Answered by banwaitharshdeep2
1

Answer:

(i) _

Given (x³−3x+7)×(2x+3)

To find the product of given expression we have to use horizontal method.

In that we have to multiply each term of one expression with each term of another

Expression so by multiplying we get,

(x³−3x+7)×(2x+3)

⇒2x(x²−3x+7)+3(x²−3x+7)

⇒2x³−6x²+14x+3x²−9x+21

⇒2x³−3x²+5x+21

(ii) _

given ( 9x²- x + 15 ) ( x²- x- 1 )

9x⁴ + 9x³ + 9 + x³ + x² + x - 15x² - 15x - 15

9x⁴ + 10x³ - 14x² - 6

Answered by Ashmitagrawal08
0

Answer:

Step-by-step explanation:

(x) ^2 + (7)^2 - 2(x) (7)

(x^2 + 49 - 14x) (2x +3)

[x^2 + (7 +7) - 14x] (2x + 3)

(x^2 + 7 + 7 - 14x) (2x + 3)

Now, by using Splitting the middle term:

= 1(x^2 + 7) + 7 (1 - 2x)

= (x^2 + 7) (1 + 7) is the answer.

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