Question

3. Find (log tan 1° + log tan 2° +
log tan 3° + - + log tan 899)​

Answer 1

Answer:

Step-by-step explanation:

logtan1+logtan2+logtan3+……………….+logtan89

=log(tan1×tan2×tan3×……………×tan89)

since loga+logb=log(a×b)

we know that tan89=tan(90-1)=cot1

Tan89=cot1

tan88=cot2

tan87=cot3

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We know that tan@×cot@=1

Therefore,

tan1×tan89=1

tan2×tan88=2

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Therefore the given question will be

log(1×1×1×1×1............×1)=log1=0.