Question

3. Find out the force P which is acting parallel to the plane (shown in Figure) in case of impending
motion. Assume u=0.25 with a smooth pulley.
​

Answer 1

Answer:

Force required for impending motion is F = 98.85 N

Explanation:

Friction force on the block placed on horizontal surface is given as

$F_f = \mu_s F_n$

here normal force on this block is same as its weight

$F_f = (0.25)(1350)$

$F_f = 337.5 N$

Now force of friction on the block placed on inclined plane is given as

$F_f = \mu (F_n)$

Here on inclined plane normal force is equal to the component of weight perpendicular to the plane

So it is given as

$F_n = 450 cos45 = 318.2$

$F_f = 0.25(318.2)$

$F_f = 79.5 N$

now by force balance we can say that net downward force along the inclined plane must balance the total friction force on two blocks for impending motion

so we have

$450 sin45 + F = 337.5 + 79.5$

$F = 98.85 N$

#Learn

Topic : Friction force

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