Question

3. Find p(-1), p (0) for each of the following polynomials :
(i) 4t⁴ +5t³–t2+6 ​

Answer 1

Answer:

7 is the correct answer

please follow

Answer 2

Step-by-step explanation:

4t⁴+5t³-t²+6

P(-1) = 4(-1)⁴+5(-1)³-(-1)²+6

= 4(1) +5(-1)-(1)+6

= 4-5-1+6

= -1 -1+6

= -2+6

= 4

4t⁴+5t³-t²+6

P(0) = 4(0)⁴+5(0)³-(0)²+6

=0+0-0+6

=6

hope it will help u