Question

3.
Find sum of n terms of the series
2.4 + 4.6 + 6.8 + .........
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Answer 1

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a = 2.4

d = 4.6-2.8

= 1.8

Therefore,

sum of n terms = n/2 [2a + (n-1)*d]

= n/2[4.8 + 1.8n - 1.8]

= n/2 (3+1.8n)

= 3n + 1.8n^2 / 2

$\boxed{Hope\:This\:Helps}$

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