Question

3. Find the 14 term of an Arithmetic progression 10.-5.-20...
620​

Answer 1

Answer:

d=(-5) -10

d=-15

a=10

an= a+(n-1) ×d

a14=10+(14-1) ×-15

=10+13×-15

=10+(-185)

=-175

Answer 2

Find :-

D = -5 - 10 = 5

From end...D = 5 and ap is -620, -615 ...10

A = -620

Then :-

So 14th term from the end = A + 13D

= -620 + 13 × 5

= -620 + 65

Final Answer :-

= - 555