Question

3. Find the area of a rhombus whose one side
is equal to 10 cm and the length of one of the
diagonals is 12 cm.​

Answer 1

The area will be 96

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Answer 2

Answer:

Hey friend, your answer is below. I hope it will help you.

Explanation:

Let the Rhombus ABCD with centre O.

from the question,

side(S) = 10 cm

shorter diagonal(P) =12 cm

consider triangle OCB,

applying Pythagoras theorem,

OC = √(BC^2-OB^2)

OC = √(10^2-6^2)

OC = √( 100-36)

OC = √64

OC = 8 cm

longer diagonal (AC) = AO+OC = 2OC = 2×8

Longer diagonal = 16 cm

Area of rhombus ABCD = [(AC×BD) / 2]

= 12×16 ÷ 2 = 96 sq.cm( answer)

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