Question

3. Find the area of a right triangle whose hypotenuse is 13 cm and one
4. Find the area of an isosceles right triangle whose equal sides are 15 cm each.
5. Find the area of an isosceles right triangle having the length of each equal side​

Answer 1

Answer:

Consider the △ABC,

whereAC=13cm;BC=12cm by phythagorus theorm

AC

2

=AB

2

+BC

2

⇒AB

2

=AC

2

+BC

2

∴AB=

13

2

−12

2

=5cm

Area of △ABC=

2

1

×base×height

=

2

1

×AB×BC=

2

1

×12×5

=30cm

2

.

Answer 2

Given:

Hypotenuse = 13cm

One side = 5cm

To Find:

Area

Formula:

The formula to find the area of right angle triangle is 1/2 base x height.

Find:

First we have to find the other side of the triangle.

A/Q Lets find:

5² + x² = 13²

25 + x² = 169

x² = 169 - 25

x² = 144

x = 12

Now we got the other side as 12cm

Solution:

1/2 x 12 x 5

6 x 5

30 cm²