3. Find the area of the triangle whose sides are 42 cm, 34 cm and 20 cm in<br />length. Hence, find the height corresponding to the longest side.
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Area of triangle by Heron's formula :-
√[ s( s - a )( s - b )( s - c )] where, s = ( a + b + c )/2
s = ( 42 + 34 + 20 ) cm / 2
= ( 96 ) cm / 2 or 48 cm
√[ 48( 48 - 42 )( 48 - 34 )(48-20)
√[ 2³ × 6 × 6 × 2 × 7 × 2² × 7 ]
= ( 2 × 2 × 2 × 6 × 7 ) cm² = 48*7 cm² or 336 cm²
Longest side = 42 cm
Area of ∆ = 1/2 × base × height
336 cm² = 1/2 × 42 cm × h
336 cm² × 2/42 cm = height
8*2 cm = h or height = 16 cm
\boxed{ Answer : height \: is \: 16 cm }
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