Question

3. Find the area of the triangle with the lengths of the sides
51 cm, 52 cm and 101 cm.​

Answer 1

Answer:

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Answer 2

area of the triangle is 510 cm ²

Step-by-step explanation:

given sides of traingle are

a= 51 cm

b = 52 cm

c = 101 cm

then perimeter of triangle = 51+ 52+101 cm = 204 cm

semi perimeter = $\frac{204}{2}$ = 102 cm

using the heron's formula

area of triangle = $\sqrt{s(s-a)(s-b)(s-c)}$

$\sqrt{102(102-51)(102-52)(102-101)}\\\\\sqrt{102(51)(50)(1)}\\\\\sqrt{2\times3\times17\times2\times5\times5\times3\times17}\\\\=2\times3\times5\times17\\\\= 510$

hence , area of the triangle is 510 cm ²

#Learn more:

If the length of side of an equilateral triangle  and a square are x cm. Find out the  perimeter and also draw a graph showing  relation between length and perimeter.

https://brainly.in/question/11254951