3. Find the area of trapezium ABCD given in
the figure below.
D.
6 cm
12 cm
6 cm
10 cm
B
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sum of triangle plus sum of rectangle
=8*6(since 8 is the hight found by Pythagorean triplet of right angle triaange)
48 is the are of tiangle and area of rectangle is 1/2*6*8=24
24+48=72
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