3. Find the average of the first 100 counting numbers.
Answers
Answered by
1
Answer:
100(100+1)÷2
100(101)÷2=10100÷2=5020
Answered by
4
Answer: The average is 50.5
Step-by-step explanation:
We can apply here the Sn formula of std 10th to get to the answer easily
So the formula states that...
Sn=n/2[2a+(n-1)d] ......(Formula)
Here Sn is the sum of the first 100 counting numbers
n is the total number of counting numbers i.e. 100
a is the first term i.e 1 obviously
d is the common difference i.e 1
Sn=100/2[2(1)+(100-1)1]
=50[2+99]
=50(101)
=5050
Therefore the sum of all the first 100 counting numbers is 5050.
Average=sum of all numbers/total counting numbers
=5050/100
=50.5
Therefore, the average is 50.5
Hope it helps you....
Pls pls mark me as the brainliest answer
Similar questions
English,
5 months ago
Math,
5 months ago
English,
5 months ago
English,
9 months ago
Business Studies,
1 year ago