Question

3. Find the average of the first 100 counting numbers.​

Answer 1

Answer:

100(100+1)÷2

100(101)÷2=10100÷2=5020

Answer 2

Answer: The average is 50.5

Step-by-step explanation:

We can apply here the Sn formula of std 10th to get to the answer easily

So the formula states that...

Sn=n/2[2a+(n-1)d] ......(Formula)

Here Sn is the sum of the first 100 counting numbers

n is the total number of counting numbers i.e. 100

a is the first term i.e 1 obviously

d is the common difference i.e 1

Sn=100/2[2(1)+(100-1)1]

=50[2+99]

=50(101)

=5050

Therefore the sum of all the first 100 counting numbers is 5050.

Average=sum of all numbers/total counting numbers

=5050/100

=50.5

Therefore, the average is 50.5

Hope it helps you....

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