Question

3.Find the base of a triangle of area 40 sq cm. and height 10 cm.​

Answer 1

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• Height = 10 cm
• Area = 40 cm²
• Base = ?

Area of Triangle = ½ × base × height

=> 40 = ½ × base × 10

=> 40 = base × 5

=> base = 40/5

=> base = 8cm

Answer 2

Answer:

Base of the triangle = 8cm

Step-by-step explanation:

Given :

• Area of ∆ = 40 cm²
• Height of ∆ = 10 cm

To find :

• Base of ∆

Answer

We know that,

$\sf Area \ of \ triangle = \dfrac{1}{2}\times base \times height$

Using this formula

$\dashrightarrow \rm 40cm^2 = \dfrac{1}{2}\times base \times 10$

$\dashrightarrow \rm 40cm^2 = base \times 5$

$\dashrightarrow \rm base = \dfrac{ 40cm^2}{5cm}$

$\dashrightarrow \rm base = 8cm$