Question

3 Find the co-ordinates of points on the x-axis which are at a distance of 5 units from the point ( 6-3).​

Answer 1

Step-by-step explanation:

hope it will help full for you

Answer 2

Answer:

Any point on X-axis has co-ordinates of form (x,0)

∴(x

1

,y

1

)=(6,−3) and (x

2

,y

2

)=(x,0) and d=5

∴d=

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

5=

(x−6)

2

+[0−(−3)]

2

=

(x−6)

2

+3

2

Squaring on both sides 5

2

(

(x−6)

2

+9

)

2

25=x

2

−12x+36+9

x

2

−12x+45−25=0⇒x

2

−12x+20=0⇒(x−10)(x−2)=0

∴x−10=0 or x−2=0⇒x=10 or x=2

∴ Required points on X-axis are (10,0) and (2,0)