Question

3 Find the compound interest of Rs 8,000 for 2 years and 4 months at the rate of10% p.a
compounded annually.​

Answer 1

Answer:-

Given

GivenP=₹8000

GivenP=₹8000R=15%p.a.

GivenP=₹8000R=15%p.a.T=2yr and 4 months 

GivenP=₹8000R=15%p.a.T=2yr and 4 months So first we will calculate for 2 yrs 

GivenP=₹8000R=15%p.a.T=2yr and 4 months So first we will calculate for 2 yrs A= p(1+r/100)^n 

GivenP=₹8000R=15%p.a.T=2yr and 4 months So first we will calculate for 2 yrs A= p(1+r/100)^n A=8000(1+15/100)²

GivenP=₹8000R=15%p.a.T=2yr and 4 months So first we will calculate for 2 yrs A= p(1+r/100)^n A=8000(1+15/100)²A=8000(115/100)²

GivenP=₹8000R=15%p.a.T=2yr and 4 months So first we will calculate for 2 yrs A= p(1+r/100)^n A=8000(1+15/100)²A=8000(115/100)²A=8000 x 115/100 x 115/100

GivenP=₹8000R=15%p.a.T=2yr and 4 months So first we will calculate for 2 yrs A= p(1+r/100)^n A=8000(1+15/100)²A=8000(115/100)²A=8000 x 115/100 x 115/100A=8x115x115x/10

GivenP=₹8000R=15%p.a.T=2yr and 4 months So first we will calculate for 2 yrs A= p(1+r/100)^n A=8000(1+15/100)²A=8000(115/100)²A=8000 x 115/100 x 115/100A=8x115x115x/10A=₹10580

GivenP=₹8000R=15%p.a.T=2yr and 4 months So first we will calculate for 2 yrs A= p(1+r/100)^n A=8000(1+15/100)²A=8000(115/100)²A=8000 x 115/100 x 115/100A=8x115x115x/10A=₹10580Now for next 4 months rate will be accordingly

r = 15\% \times \frac{4}{12} \\ \\ = 15 \times \frac{1}{3} \\ \\ = 5\%\end{lgathered}$$ 

r = 15\% \times \frac{4}{12} \\ \\ = 15 \times \frac{1}{3} \\ \\ = 5\%\end{lgathered}$$ Interest = pxrxt /100

r = 15\% \times \frac{4}{12} \\ \\ = 15 \times \frac{1}{3} \\ \\ = 5\%\end{lgathered}$$ Interest = pxrxt /100Here P= amount we got after 2 years I.e. =10580

r = 15\% \times \frac{4}{12} \\ \\ = 15 \times \frac{1}{3} \\ \\ = 5\%\end{lgathered}$$ Interest = pxrxt /100Here P= amount we got after 2 years I.e. =10580R=5%

r = 15\% \times \frac{4}{12} \\ \\ = 15 \times \frac{1}{3} \\ \\ = 5\%\end{lgathered}$$ Interest = pxrxt /100Here P= amount we got after 2 years I.e. =10580R=5%T=1

r = 15\% \times \frac{4}{12} \\ \\ = 15 \times \frac{1}{3} \\ \\ = 5\%\end{lgathered}$$ Interest = pxrxt /100Here P= amount we got after 2 years I.e. =10580R=5%T=1=10580x5x1/100

r = 15\% \times \frac{4}{12} \\ \\ = 15 \times \frac{1}{3} \\ \\ = 5\%\end{lgathered}$$ Interest = pxrxt /100Here P= amount we got after 2 years I.e. =10580R=5%T=1=10580x5x1/100=₹529

r = 15\% \times \frac{4}{12} \\ \\ = 15 \times \frac{1}{3} \\ \\ = 5\%\end{lgathered}$$ Interest = pxrxt /100Here P= amount we got after 2 years I.e. =10580R=5%T=1=10580x5x1/100=₹529Amount after 2yr and 4 months =10580+529

r = 15\% \times \frac{4}{12} \\ \\ = 15 \times \frac{1}{3} \\ \\ = 5\%\end{lgathered}$$ Interest = pxrxt /100Here P= amount we got after 2 years I.e. =10580R=5%T=1=10580x5x1/100=₹529Amount after 2yr and 4 months =10580+529=₹11109

r = 15\% \times \frac{4}{12} \\ \\ = 15 \times \frac{1}{3} \\ \\ = 5\%\end{lgathered}$$ Interest = pxrxt /100Here P= amount we got after 2 years I.e. =10580R=5%T=1=10580x5x1/100=₹529Amount after 2yr and 4 months =10580+529=₹11109Compound interest = amount - principal

r = 15\% \times \frac{4}{12} \\ \\ = 15 \times \frac{1}{3} \\ \\ = 5\%\end{lgathered}$$ Interest = pxrxt /100Here P= amount we got after 2 years I.e. =10580R=5%T=1=10580x5x1/100=₹529Amount after 2yr and 4 months =10580+529=₹11109Compound interest = amount - principal=11109-8000

r = 15\% \times \frac{4}{12} \\ \\ = 15 \times \frac{1}{3} \\ \\ = 5\%\end{lgathered}$$ Interest = pxrxt /100Here P= amount we got after 2 years I.e. =10580R=5%T=1=10580x5x1/100=₹529Amount after 2yr and 4 months =10580+529=₹11109Compound interest = amount - principal=11109-8000=₹3109