3. Find the compound interest on 24,000 at 15% per
annum for 7/3 years compounded annually.
Answers
Answer:
METHOD 1: Without formula
Principal = Rs 24000
Interest rate = 15%
Time = 7/3 = 2 1/3
At the end of 1 year:
Principal + Interest = 24000 + (0.15 x 24000) = Rs 27600
At the end of 2 year:
Principal + Interest = 27600 + (0.15 x 27600) = Rs 31740
At the end of 2 1/3 year:
Principal + Interest = 31740 + 1/3 (0.15 x 31740) = Rs 33327
Compound Interest = 33327 - 24000 = Rs 9327
Answer: Compound Interest = Rs 9327
METHOD 2 : With Formula
Amount = 24000 × (1 + 15/100)² × [1 + (1/3 × 15)/100]
Amount = Rs 33327
Compound Interest = 33327 - 24000 = Rs 9327
Answer: Compound Interest = Rs 9327
hope it helps u !!
Principal=P=24,000
Rate of interest=r=15%
Time=n= 7/3 years
Here first we take n=2years
A=P(1+r /100)^n where A=Amount and n=number of years
A=24000(1+15/ 100)² =24000×115 /100×115/100=Rs.31,740
The amount after 2 years is Rs31,740
Now principal=Rs.31,740
Simple interest for last 1/3 year is PRT /100=31,740×15 /100×1 /3= Rs.1,587
∴ Amount after 2 1/3 year= Rs.31740+1587= Rs.33,327
C.I =A−P
∴C.I=33,327−24,000=Rs.9,327
∴ the compound interest is Rs.9,327