3. Find the coordinates of the circumcentre of the triangle whose vertices
are (1, 1), (2, -1) and (3,2).
Answers
Answered by
0
Answer:
Let the coordinates of the vertices of the triangle are A(1,1),B(2,−1) and C(3,2)
Now, Lets find the distance between each of the three points.
We will use the distance formula to find the distance between AB,BC and AC
Thus AB=
(2−1)
2
+(−1−1)
2
=
5
BC=
(3−2)
2
+(2+1)
2
=
10
AC=
(3−1)
2
+(2−1)
2
=
5
NowAB
2
+AC
2
=10=BC
2
Thus it form a right angled triangle, right angled at A.
Now the circumcentre will be the mid-point of the hypotenuse BC.
Thus mid-point of BC is (
2
2+3
,
2
−1+2
)=(
2
5
,
2
1
).
And the circumradius is the half the length of BC
⇒ Circumradius =
2
10
Answered by
0
Answer:
Circumcentre of the triangle ABC,
(x,y) = (2,1)
refer to the attachment
Attachments:
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