3. Find the distance between the following lines and points :
(i) 4x + 3y - 5 = 0; (-2,-1) (ii) 5x + 12y - 41 = 0; (3, 0)
(iii) 73 x + y = 10; (3, 4)
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Answer:
Hey
Step-by-step explanation:
4x+3y+10=0 ---- (1)
5x-12y+26=0 ----- (2)
7x+24y=50 ------ (3)
The distance between origin & line (1) = ∣
16+9
4×0+30+10
∣=
5
10
=2
The distance between origin & line (2) = ∣
25+144
5×0−12×0+26
∣=
13
26
=2
The distance between origin & line (3) = ∣
(24)
2
+(7)
2
7×0+24×0−50
∣=
25
50
=2
∴ This distance between origin & all three lines is same.
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