Question

3 Find the distance between the points
P (cosa, -sin a) and Q(-cosa, sina).​

Answer 1

Answer:

(pQ)^2 = (acha A - acosA)^2 + {asinA-(-asinA)}^2

=0^2 + (2asinA)^2

pQ =√(2asinA)^2

pQ= √4a^2sin^2A

pQ= 2asinA

thank you