Question

3) Find the distance between the points PC-1, 1) and Q 15,-7)​

Answer 1

Step-by-step explanation:

P(-1, 1) Q(15, -7)

Here, x1 = -1, x2 = 15, y1 = 1 and y2 = -7

$Distance = \sqrt{(x2 - x1) {}^{2} + {(y2 - y1)}^{2} }$

$= \sqrt{(15 - ( - 1) {}^{2} + (( - 7) - 1) {}^{2} }$

$= \sqrt{ {16}^{2} + ( - 8) {}^{2} }$

$= \sqrt{256 + 64} = \sqrt{320}$

$= \sqrt{16 \times 4 \times 5}$

$= 8 \sqrt{5}\: units$