Question

3)
Find the distance travelled by a body before coming
to rest if it is moving with a velocity of
15mls and coefficient of friction b/w the ground
and body is 0.45

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Answer 1

Answer:

33.33 answer of the question

Answer 2

Answer:

25.51m

Explanation:F=m×a

F=U×N=U×m×g

m×a= -U×m×g

a= -0.45×9.8

a= -4.41

V²=U²-2as

15²=0²-2(-4.41)

225=8.82S

S=225/8.82

S=25.51m