Question

(3) Find the equation of a tangent to the circle
x2 + y2 - 3x + 2y = 0 at the origin.​

Answer 1

Step-by-step explanation:

Accordingly, here in the present case, the equation of the tangent line at (x', y') is : xx' + yy' - (3/2)(x+x') + (y+y') = 0 . Putting (x', y') = (0, 0), we get, the required equation of the tangent at the point(0, 0) as ; -(3/2)x + y = 0 or 2y = 3x .