Question

3] Find (the equation of the tangent and normal line to the curve
= x^3+e^x at x=0

Answer 1

Answer:

Tangent equation is

y-1=1(x-0)

y=x+1

Step-by-step explanation:

y = x^3+e^x

dy/dx=3x^2+e^x

At x=0,

dy/dx=0+1=1

Also y=0+1=1

Tangent equation is

y-1=1(x-0)

y=x+1