Question

3 Find the equation of the tangent to
y=5/e^2x+3 at x=0

Answer 1

Step-by-step explanation:

when x = 0, y = 1

Thus, the point is (0, 1)

Now, dy/dx = 2.5/e^2x

Thus, m = (dy/dx)x=0 = 2.1 = 2

Hence, the equation of the tangent is

y – 1 = 2 (x – 0)

⇒ y = 2x + 1