3.Find the force between two charges when they are brought in
contact and separated by 4cm apart, charges are 2nC and -1nC,
in μN.
Answers
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Explanation:
Charge on the first sphere, q
1
=2×10
−7
C
Charge on the second sphere, q
2
=3×10
−7
C
Distance between the spheres, r=30cm=0.3m
F=
4πε
0
r
2
q
1
q
2
Where, ε
0
= Permittivity of free space
4πε
0
1
=9×10
9
Nm
2
C
−2
F=
(0.3)
2
9×10
9
×2×10
−7
×3×10
−7
=6×10
−3
N
Hence, force between the two small charged spheres is 6×10
−3
N. The charges are of same nature. Hence, force between them will be repulsive.
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