Question

3. Find the G.P: whose 4th term is - 3 and 7th term is 1/9.​

Answer 1

Step-by-step explanation:

nth term of gp

$= a {r}^{n - 1}$

therfore,ATQ,

$a {r}^{3 } = - 3$

and

$a {r}^{6} = \frac{1}{9 }$

dividing the two equations,we get

${r}^{3} = \frac{ - 1}{27}$

giving

$r = \frac{ - 1}{3}$

therefore a=81. hence gp is 81,-27,9,-3,1......