Question

3.
Find the greatest number that can divide 1624,522 and 1276 leaving no remainder in
each case.
.​

Answer 1

Given number:

• 1624, 522 and 1276.

To Find:

• The greatest number that can divide leaving no remainder in each case.

Finding the greatest number:

Using prime factorisation.

• Factors of 1624 = 2³ × 7 × 29
• Factors of 522 = 2 × 3² × 29
• Factors of 1276 = 2² × 11 × 29

HCF (1624, 522, 1276) = 2 × 29 = 58

Hence,

• The greatest number is 58.

Answer 2

Question:-

• Find the greatest number that can divide 1624,522 and 1276 leaving no remainder in each case.

To Find:-

• Find the greatest number.

Solution:-

Given ,

• $\sf \: { 1 }^{ st } \: number = 1624$

• $\sf \: { 2 }^{ nd } \: number = 522$

• $\sf \: { 3 }^{ rd } \: number = 1276$

Now ,

We have to find the greatest number:-

$\dashrightarrow\sf \: 1624 = { 2 }^{ 3 } \times 7 \times 29$

$\dashrightarrow\sf \: 522 = 2 \times 3 \times 3 \times 29$

$\dashrightarrow\sf \: 1276 = 2 \times 2 \times 11 \times 29$

Hence ,

• The greatest number is 2 × 29 = 58.