Question

3. Find the H.C.F of 217 and 686.​

Answer 1

Answer:

The H. C. F of 217 and 686 is 7. Hope it helps you.

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Answer 2

Answer:

$to \: find \: hcf \: we \: have \: to \: \\ do \: prime \: factorization \: of \\ \: both \: the \: given \: no \: or \\ \: we \: can \: find \: by \: the \: \\ algorithm$

factorization method:-

• 217 = 7×31
• 686 = 2×7×7×7.
• here 7 is common so 7 is HCF.

algorithm method:-

• a = bq + r ---- equation of algorithm---- where a and b are the two no. and q is question and r is remainder.
• 686=217×3+35
• 217= 35×6+7
• 35= 7×5+0
• here remainder is 0. So, 7 is the HCF.

HCF, 7