3. Find the HCF of the following by prime factorization : A 12 15 18 b18 45 63
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SOLUTION:
i) 18,48
18=2\times3\times318=2×3×3
48=2\times2\times2\times2\times348=2×2×2×2×3
The common factor of 18 and 48 are 2,3. thus, HCF of 18 and 48 is2\times3=62×3=6
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Answer:
3. Find the HCF of the following by prime factorization : A 12 15 18 b18 45 63
Step-by-step explanation:
6
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