Question

3. Find the height of the tower if length of the shadow is 10 m and sun’s altitude is 45

Answer 1

Let AB be the tower of height 10m and BC be the shadow.

Then, $\sf{\angle{ACB}=45°}$

From right ∆ABC, we have

$\longrightarrow$ $\sf{\tan(45)° = \frac{AB}{BC}}$

$\longrightarrow$ $\sf{1 = \frac{10}{BC}}$

$\longrightarrow$ $\sf{BC=10m}$

Hence, the length of the shadow is 10m.