Math, asked by rakbathsanga, 11 months ago

3
Find the largest positive integer which divides 615 and 963 leaving remainder 6 in each case.



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Answers

Answered by abhishesumesh
3

Answer:

It is given that required number when divides 615 and 963, the remainder is 6 in each case. ⇒ 615 - 6 = 609 and 963 - 6 = 957 are completely divisible by the required number. Since, it is given that the required number is the largest number.

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Answered by supreet57
2

Answer:

-6

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