Question

3. Find the LCM.
(36, 42 (ii) 15, 25, 30 (iii) 18, 42, 48 (iv) 4, 12, 20 (v) 24, 40, 80, 120
Find the smallest number which when divided by 8, 9, 10, 15, 20 gives a remainder​

Answer 1

Here, the smallest number for division is LCM of 8, 9, 10,15 and 20. 8 = 2 x 2 x 2 9 = 3 x 3 10 = 2 x 5 15 = 3 x 5 20 = 2 x 2 x 5 LCM of given numbers = 2 x 2 x 2 x 3 x 3 x 5 = 360 ∴ Required, smallest number = LCM + Remainder = 360 + 5 = 365 ∴ The required smallest number is 365.

iv. is correct