3. Find the least number of five digits which on dividing by 4, 12, 20 and 24 leaves remainder 3 in each case.
Answers
Step-by-step explanation:
LCM of 4,12, 20 and 24=120.
So the least five digit number divisible by our would be divisible by 120.
If we multiply 120 by 100 we get 12000 which is 5 digits.
Now let us using trial and error method find whether numbers below 100 when multiplied get a 5 figure number. Let us lessen the number of steps by multiplying using 90,first.
120*90=10800
So now we can reduce the number again.
120*85=10200
As this is very close to 10000 we can reduce the number to be multiplied by 1.
120*84=10080
One more time
120*83=9960
So as this is not a 5-digit number we can make sure that
120*83 .i.e 10080 is the smallest 5-digit number divisible by 4,12,20 and 24.
Answer:
10000 is answer
Step-by-step explanation:
Least 5 digit number = 10000. LCM(4,12,20,24) = 120.