3. Find the LSA and TSA of the cylinders with the following dimensions.
a.Radius=3.5m,Height=10m
b.Radius=10.5 cm, Height = 15 cm
c.Radius=7m,Height=25m
d. Radius = 70 cm, Height = 1 m
e. Radius = 21 m, Height = 30 cm
f.Radius=14cm,Height=50cm
Answers
Step-by-step explanation:
a. radius =3.5m, height=10m= LSA= 2pirh= 2*22/7*3.5*10= 2*22/7*35/10*10= 2*22/7*35 = 2*22*5= 220m square
tsa of cylinder=2pir(h+r)= 2*22/7*3.5(10+3.5)= 2*22/7*35/10(13.5)= 297m square
b. radius=10.5cm height= 15cm= LSA=2pirh= 2*22/7*10.5*15= 2*22/7*105/10*15= 990m square
tsa of cylinder=2pir(h+r)= 2*22/7*10.5*(15+10.5)= 1485m square
c. radius=7m, height= 25m=LSA=2pirh=2*22/7*7*25= 2*22*25 = 1100m square
tsa of cylinder = 2pir(h+r)= 2*22/7*7(25+7) = 2*22*(32) = 44*32= 1408m square
d. radius = 70cm, height= 1m =100cm LSA=2pirh= 2*22/7*70*100 = 2*22*10*1000= 44*1000= 44000cm square or 44 m square
tsa= 2pir(h+r)= 2*22/7*70(70+100)= 74800cm square
e. radius= 21m, height= 30cm = 30/100= 0.3m= LSA=2pirh= 2*22/7*21*0.3=39.6 m square
tsa= 2pir(h+r)= 2*22/7*70(100+70)= 2*22*10(170)= 44*1700=74800m square
f. radius = 14cm, height = 50cm = LSA= 2pirh= 2*22/7*14*50= 4400cm square
TSA= 2pir(h+r)= 2*22/7*14(14+50)= 88(64)= 5632m square
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