Question

3. Find the nature of the roots for the quadratic equation.
2x² - 6x +3=0​

Answer 1

Answer:

the roots are .0 and 12 .

Answer 2

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Given :-

a = 2 , b = -6 and. c = 3.

A/Q,

$d = {b}^{2} - 4ac. \\ \\ \: \: \: = { - 6}^{2} - 4(2)(3). \\ \\ \: \: \: = 36 - 24. \\ \\ \: \: \: = 12.$

Hence:-

D >0

Have real roots

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