Question

3. Find the number of zeroes of the polynomial Q (y) =y² -1​

Answer 1

Answer:

Q (y)=y^2-1

a^2-b^2=(a+b)(a-b)

Q (y)=(y+1)(y-1)

IF (y+1)=0

then y= -1

IF (y-1)=0

then y=1

hope you understand

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Answer 2

y = 1 and y= -1


As square of -1 is 1 it will be verified