Question

3.) Find the probability of getting (i) 9 (ii) 7 and (iii) 6 on
throwing two dice.
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Answer 1

Answer:

36 outcomes

i) getting 9 by throwing 2 dices = 4

thus, probablity = 4/36 = 1/9

ii) getting 7 by throwing 2 dices = 6

thus, probablity = 6/36 = 1/6

iii)getting 6 by throwing 2 dices = 5

thus, probablity = 5/36

Answer 2

Step-by-step explanation:

Total outcomes of throwing two dice=6^2=36

bcoz a dice has six faces with six numbers

(1)The probability of getting 9 as sum are in cases (3,6) (4,5) (5,4) (6,3)

so,getting 9=4

favourable outcomes/total outcomes

4/36=1/9

(2) probability of getting 7 are in cases (1,6) (2,5) (3,4) (4,3) (5,2) (6,1)

favourable outcomes=6

6/36=1/6

(3) probability of getting 6 are in cases (1,5) (2,4) (3,3) (4,2) (5,1)

favourable outcomes=5

5/36