Question

-3. Find the quadradic equation whose are (6+√5) and (6-√5)​

Answer 1

Answer:

quadratic equation is

x² + (sum of roots)x + (product of roots) = 0

sum of roots = 6+√5+6-√5 = 12

product of roots = 36-5 = 31

so, equation is

x²+12x+31 = 0