Question

3. Find the quadratic polynomials whose zeros are-
1/3 and -1​

Answer 1

Answer:

1/3

Step-by-step explanation:

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Answer 2

Answer: 1/3

Let α=1andβ=−3.α=1andβ=-3.

Sum of zeros = (α+β)=1+(−3)=−2.(α+β)=1+(-3)=-2.

Product of zeros = αβ=1×(−3)=−3.αβ=1×(-3)=-3.

So, the required polynomial is

x2−(α+β)x+αβ=x2−(−2)x+(−3)x2-(α+β)x+αβ=x2-(-2)x+(-3)

=x2+2x−3.=x2+2x-3.

Sum of zeros =−2=−21=−(coefficient of x)(coefficient of x2),=-2=-21=-(coefficient of x)(coefficient of x2),

product of zeros =−3=−31=constant termcoefficient of x2.