Question

3. Find the ratio in which point T(-1, 6)divides the line segment joining the points
P(-3, 10) and Q(6, -8).​

Answer 1

Answer:

R.E.F image  

Let T divides PQ in  

′

λ:1" ratio

∴ (  

λ+1

6λ−3

​  

)=−1  [By section formula]

⇒6λ−3=−λ−1

⇒7λ=2

⇒[λ=2/7]

Hence ratio is [2:7].

Step-by-step explanation:

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Answer 2

☯ Explanation,

Point T(-1, 6) divides the line segment joining the points P(-3, 10) and Q(6, -8).

Where,

⇒ T(-1 , 6) = (x , y)

⇒ P(-3 , 10) = (x1 , y1)

⇒ Q(6 , -8) = (x2 , y2)

Applying section formula,

⇒ x = (mx2 + nx1)/(m + n)

[ Put the values ]

⇒ -1 = (m × 6 + n × (-3))/(m + n)

⇒ -1(m + n) = 6m - 3n

⇒ -m - n = 6m - 3n

⇒ -n + 3n = 6m + m

⇒ 2n = 7m

⇒ m : n = 2 : 7

☯ Hence,

The ratio of joining segment is 2 : 7.